The Books Insiderindependent audiobook data
Who Is J.K. Rowling? by Meg Belviso, Pamela D. Pollack

Who Is J.K. Rowling?: Audiobook

According to The Books Insider's catalog data, the Who Is J.K. Rowling? audiobook runs 1.1 hours unabridged, narrated by Cassandra Campbell (about 0.7 hours at 1.5× playback speed).

1.1listening hrs
Non-fiction (Kids)store shelf
2016released
Free for new listeners

The instrument When will you finish it?

Based on 1.1 hours of listening.

Days to finish Who Is J.K. Rowling? at common listening paces
Your paceYou'll finish in
30 min / day3 days
1 hour / day2 days
2 hours / day1 day
1 hour / day at 1.5×1 day

Part of The Audiobook Finish-Time Calculator: the same instrument for any audiobook we measure.

What our data says

  • At 1.1 hours, it is shorter than 60% of the 14,091 Non-fiction (Kids) audiobooks in our catalog.

More narrated by Cassandra Campbell

Cassandra Campbell narrates 1,083 unabridged audiobooks in our catalog, 11,240 hours in all.

All Cassandra Campbell audiobooks, measured

Computed from 409,794 English-language unabridged audiobooks in The Books Insider catalog (store data read November 3, 2026). Lengths are the store's own running times. Methodology.

About this listen

Who Is J.K. Rowling? is an audiobook by Meg Belviso and Pamela D. Pollack: a 1.1-hour unabridged recording, read by Cassandra Campbell, released June 7, 2016, on the Non-fiction (Kids) shelf.

The listen at a glance

Length
1.1 hrs
Narrated by
Cassandra Campbell
Released
June 7, 2016
Format
Unabridged audiobook
Language
English
Store shelves
Non-fiction (Kids)
ISBN
9780735205499

How to listen to Who Is J.K. Rowling? free

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Questions listeners ask

How long is the Who Is J.K. Rowling? audiobook?

Who Is J.K. Rowling? runs 1.1 hours unabridged. At 1.5× speed that drops to roughly 0.7 hours.

Is the Who Is J.K. Rowling? audiobook free?

Yes, for new listeners: the trial starts you with three free audiobooks.

Who narrates Who Is J.K. Rowling??

Who Is J.K. Rowling? is narrated by Cassandra Campbell.